SOLUTION: Trina can ride 48 mi on her bike against the wind. With the wind at her back, she rides 4 mph faster and can ride 60 mi in the same amount of time. Find her speed riding against th
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Question 960542: Trina can ride 48 mi on her bike against the wind. With the wind at her back, she rides 4 mph faster and can ride 60 mi in the same amount of time. Find her speed riding against the wind, and her speed riding with the wind.
What I have written so far:
48 mi--against 4 mph slower
60 mi--with and 4 mph faster Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Trina can ride 48 mi on her bike against the wind. With the wind at her back, she rides 4 mph faster and can ride 60 mi in the same amount of time. Find her speed riding against the wind, and her speed riding with the wind.
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let x=Trina's speed against the wind
x+4=Trina's speed with the wind
travel time=distance/speed
..
60x=48x+192
12x=192
x=16
16+4=20
Trina's speed against the wind=16 mph
Trina's speed with the wind=20 mph
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