SOLUTION: Find three consecutive odd integers such that the smallest is equal to 16 more than one fifth of the greatest.

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Question 960087: Find three consecutive odd integers such that the smallest is equal to 16 more than one fifth of the greatest.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

x-2 = 16 + (x+2)/5
x - 2 = 16 + x/5 + 2/5
4x/5 = 92/5
x = 23

The integers are 21, 23, and 25.