SOLUTION: I tried and I really don't get how to do these types of problems I would appreciate if someone answers my question and shows me how to do it and thank you
Heidi sold 56 tickets
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Heidi sold 56 tickets
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Question 960020: I tried and I really don't get how to do these types of problems I would appreciate if someone answers my question and shows me how to do it and thank you
Heidi sold 56 tickets to a play and collected $215.00 adult tickets cost $4.50 each and student tickets cost $3.50 each how many tickets of each kind did she sell? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
A=adult tickets; C=child tickets
A+C=56
A=56-C
$4.50A+$3.50C=$215 Substitute for A
$4.50(56-C)+$3.50C=$215
$252-$4.50C+$3.50C=$215 Subtract $252 from each side.
-$1.00C=-$37 Divide each side by(-$1)
C=37 ANSWER 1: She sold 37 child tickets.
A=56-C=56-37=19 ANSWER 2: She sold 19 Adult tickets.
CHECK:
$4.50A+$3.50C=$215.00
$4.50(19)+$3.50(37)=$215.00
$85.50+$129.50=$215.00
$215=$215
