SOLUTION: A ladder of length 15 ft is placed against a building in such a way that the distance from the top of the ladder to the ground is 12ft. Find the distance from the bottom of the lad

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Question 96: A ladder of length 15 ft is placed against a building in such a way that the distance from the top of the ladder to the ground is 12ft. Find the distance from the bottom of the ladder to the building.

The length of a rectangular frame is 7 cm more than the width. the area inside the frame is 98 square cm. Find the width of the frame.
PLEASE HELP !!
Answer by terrtwo(10) About Me  (Show Source):
You can put this solution on YOUR website!
+graph%28+600%2C+400%2C+-4%2C+20%2C+-4%2C+20%2C+-12%2F13x+%2B+12%29+
Since the ladder is leaning against a wall and we are given the height of the ladder, as well as how high is sits while leaning on the wall, we are able to form a right triangle. The original height of the ladder, which is now leaning, is the hypothenus. The height upward on the wall is the height from the ground and the vertical side. The remaining side of the triangle, the distance from the foot of the wall to the foot of the ladder is the distance we are seeking.
Using the Pythagorean theory (x^2 + y^2) = z^2, we realize that z is equal to 15, and that either of the remaining sides (I'll choose x) can be 12.
Thus 12%5E2+%2B+y%5E2+=+15%5E2 --> 144+%2B+y%5E2+=+225.
We subtract 144 from both sides --> 144+%2B+y%5E2+-+144+=+225+-+144+ --> y%5E2+=+169.
We take the square root of both sides --> sqrt%28y%5E2%29+=+sqrt%28169%29 --> y = 13