SOLUTION: When f(x)= x ______ x^2-25 the vertical asymptotes is 5 but when i do the horizontal asymptotes it comes out to only the denominator comes out as x. For the answer h

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Question 959613: When f(x)=
x
______
x^2-25
the vertical asymptotes is 5
but when i do the horizontal asymptotes it comes out to only the denominator comes out as x. For the answer how would i write it down?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First off, the vertical asymptotes are x=5 and x=-5.
Now for horizontal, divide the numerator and denominator by the highest term of either.
%28x%29%2F%28x%5E2-25%29=%28x%2Fx%5E2%29%2F%28%28x%5E2-25%29%2Fx%5E2%29
.
.
%28x%29%2F%28x%5E2-25%29=%281%2Fx%29%2F%281-25%2Fx%5E2%29
.
.
Now take the limit as x goes to infinity,
%28x%2Fx%5E2%29%2F%28%28x%5E2-25%29%2Fx%5E2%29=%280%29%2F%281-0%29
.
.
%28x%2Fx%5E2%29%2F%28%28x%5E2-25%29%2Fx%5E2%29=%280%29%2F%281%29
.
.
%28x%2Fx%5E2%29%2F%28%28x%5E2-25%29%2Fx%5E2%29=highlight%280%29
.
.
.
graph%28300%2C300%2C-20%2C20%2C-3%2C3%2Cx%2F%28x%5E2-25%29%29