SOLUTION: solve for x: log2(8x)-log2(x^2-1)=log2(3)

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Question 959458: solve for x:
log2(8x)-log2(x^2-1)=log2(3)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%282%2C%288x%29%29-log%282%2C%28x%5E2-1%29%29=log%282%2C%283%29%29
log%282%2C%288x%29%2F%28x%5E2-1%29%29=log%282%2C%283%29%29...if log same, then
8x%2F%28x%5E2-1%29=3
8x=3%28x%5E2-1%29
8x=3x%5E2-3
0=3x%5E2-8x-3
3x%5E2-9x%2Bx-3=0
%283x%5E2-9x%29%2B%28x-3%29=0
3x%28x-3%29%2B%28x-3%29=0
%283x%2B1%29%28x-3%29=0
solutions:
%283x%2B1%29=0=>3x=-1=>x=-1%2F3(assuming a complex-valued logarithm)
%28x-3%29=0=>x=3