SOLUTION: A jet plane flying with the wind flew 2200 km in 4 hours. Flying against the wind, the plane could fly only 1820 km in the same amount of time. Find:
a) The rate of the plane in c
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a) The rate of the plane in c
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Question 959269: A jet plane flying with the wind flew 2200 km in 4 hours. Flying against the wind, the plane could fly only 1820 km in the same amount of time. Find:
a) The rate of the plane in calm air and,
b) The rate of the wind
You can put this solution on YOUR website! R=rate of plane; W=rate of wind
R+W=2200km/4hrs=550km/hr
R-W=1820km/4hrs=455 km/hr
R-W=455km/hr Add W to each side.
R=455km/hr+W
R+W=550km/hr Substitute for R.
455km/hr+W+W=550km/hr Subtract 455km/hr from each side.
2W=95km/hr Divide each side by 2.
W=47.5 km/hr ANSWER B): Speed of the wind was 47.5 km/hr.
R=455km/hr+W=455km/hr+47.5km/hr=502.5km/hr
ANSWER A): The rate of the plane in calm air was 502.5 km/hr.
CHECK:
2200km/(502.5km/hr+47.5km/hr)=1820km/(502.5km/hr-47.5km/hr)
2200km/(550km/hr)=1820km/(455km/hr)
4hrs=4hrs
You can put this solution on YOUR website! A jet plane flying with the wind flew 2200 km in 4 hours. Flying against the wind, the plane could fly only 1820 km in the same amount of time. Find:
a) The rate of the plane in calm air and,
b) The rate of the wind
travel time=distance/rate
***
let x= rate of the plane in calm air
let c= rate of the wind
(x+c)=rate of plane with wind
(x-c)=rate of plane against wind
..
4(x+c)=2200
4(x-c)=1820
..
4x+4c=2200
4x-4c=1820
add
8x=4020
x=502.5
..
subtract:
8c=380
c=47.5
rate of the plane in calm air=505.2 km/h
rate of the wind =47.5 km/h
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