SOLUTION: Consider the function f(x)=-2x^2-8x+2 Find the Vertex.

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Question 959155: Consider the function f(x)=-2x^2-8x+2 Find the Vertex.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
Answer by MathTherapy(10552) About Me  (Show Source):
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Consider the function f(x)=-2x^2-8x+2 Find the Vertex.
f%28x%29+=+-+2x%5E2+-+8x+%2B+2

x-coordinate of the vertex is at: x+=+-+b%2F%282a%29

x+=+-+-+8%2F%282+%2A+-+2%29

x+=+8%2F%28-+4%29, or x+=+-+2



f%28x%29+=+-+2x%5E2+-+8x+%2B+2

f%28-+2%29+=+-+2%28-+2%29%5E2+-+8%28-+2%29+%2B+2 ------- Substituting - 2 for x 

f%28-+2%29+=+-+2%284%29+%2B+16+%2B+2

f%28-+2%29+=+-+8+%2B+16+%2B+2

f%28-+2%29+=+10

Vertex is found at the coordinate point: (highlight_green%28-+2%29%22%2C%22highlight_green%2810%29)