Question 959154: a) The perimeter of a rectangular field is 120 meters. Its length is 10 meters more than its width. Find the length and width of this rectangle?
b) Going for a long trip, Joshua drove for 3 hours and had lunch. After lunch he drove for 4 more hours at a speed that is 10 km/h more than before lunch. The total trip was 600 km.
i. What was his speed before lunch?
ii. What distance did he drive after lunch?
can i have the solution as well. Thanks
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! a) Perimeter(P) = 2l +2w where l is length and w is width
we are given l = w +10, therefore
2(w+10) + 2w = 120
2w +20 +2w = 120
4w = 100
w = 25 and
length is 35 meters and width is 25 meters
b) we use the formula rate * time = distance, let
r be Joshua's rate before lunch and r+10 is his rate after lunch, therefore
3r + 4(r+10) = 600
3r +4r +40 = 600
7r = 560
r = 80
i) Joshua's speed before lunch is 80 km per hour
ii) after lunch,
4(r+10) = 4(80+10) = 360 km
Joshua travels 360 km after lunch
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