SOLUTION: at a concession stand, three hot dogs and four hamburgers cost $9.75; four hot dogs and three hamburgers cost $9.50. Find the cost of one hot dog and the cost of one hamburger.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: at a concession stand, three hot dogs and four hamburgers cost $9.75; four hot dogs and three hamburgers cost $9.50. Find the cost of one hot dog and the cost of one hamburger.      Log On


   

Question 959095: at a concession stand, three hot dogs and four hamburgers cost $9.75; four hot dogs and three hamburgers cost $9.50. Find the cost of one hot dog and the cost of one hamburger.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
at a concession stand, three hot dogs and four hamburgers cost $9.75; four hot dogs and three hamburgers cost $9.50. Find the cost of one hot dog and the cost of one hamburger.
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Equations:
3d + 4h = 975 cents
4d + 3h = 950 cents
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Modify for elimination:
12d + 16h = 4*975
12d + 9h = 3*950
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Subtract and solve for "h"::
7h = 1050
h = $1.50 (cost of one hamburger)
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Solve for "d"::
3d + 4h = 975
3d + 4*150 = 975
3d = 375
d = $1.25 (cost of one hot dog)
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Cheers,
Stan H.
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