SOLUTION: Log2 (x+5)-log2(2x-1)=5

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Question 959037: Log2 (x+5)-log2(2x-1)=5
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%282+%2C%28x%2B5%29%29-log%282%2C%282x-1%29%29=5
log%282+%2C%28x%2B5%29%2F%282x-1%29%29=5....change the base to base 10
log%28%28x%2B5%29%2F%282x-1%29%29%2Flog%282%29=5
log%28%28x%2B5%29%2F%282x-1%29%29=5log%282%29
log%28%28x%2B5%29%2F%282x-1%29%29=log%282%5E5%29
log%28%28x%2B5%29%2F%282x-1%29%29=log%2832%29........if log same, then
%28x%2B5%29%2F%282x-1%29=32.........solve for x
x%2B5=32%282x-1%29
x%2B5=64x-32
32%2B5=64x-x
37=63x
x=37%2F63

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Log2 (x+5)-log2(2x-1)=5
log+%282%2C+%28x+%2B+5%29%29+-+log+%282%2C+%282x+-+1%29%29+=+5

log+%282%2C+%28%28x+%2B+5%29%2F%282x+-+1%29%29%29+=+5

%28x+%2B+5%29%2F%282x+-+1%29+=+2%5E5

%28x+%2B+5%29%2F%282x+-+1%29+=+32

32(2x – 1) = x + 5

64x – 32 = x + 5

64x – x = 5 + 32

63x = 37

highlight_green%28x+=+37%2F63%29