SOLUTION: three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B

Algebra ->  Rate-of-work-word-problems -> SOLUTION: three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B       Log On


   



Question 958982: three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B together can do a job in ____ minutes.
Found 2 solutions by josgarithmetic, Edwin McCravy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Let a, b, c, be the times for each to do 1 job if each alone.


Three equations in three unknown variables. The question is to find the reciprocal of 1%2Fa%2B1%2Fb.

Could you try using the last equation to eliminate c, and have or make a simpler system? I have not worked through this; only setup the system.

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
three men A B C working together can do a job in 6 hrs less time than A alone, in 1 hr less time than B alone and in one half the time needed by C when working alone. then A and B together can do a job in.
Let x = the number of hours it takes A to do 1 job working alone.
Let y = the number of hours it takes B to do 1 job working alone.
Let z = the number of hours it takes C to do 1 job working alone.
Let t = the number of hours it takes A,B, and C to do 1 job working together.

Then

three men A B C working together can do a job in 6 hrs less time than A alone,
      t = x - 6
(1)   x = t + 6

in 1 hr less time than B alone
      t = y - 1
(2)   y = t + 1

and in one half the time needed by C when working alone.
      t = z%2F2 
     2t = z
(3)   z = 2t      

A's working rate = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2Cx%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2Fx%2Cjob%2Fhr%29+ 

B's working rate = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2Cy%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2Fy%2Cjob%2Fhr%29+

C's working rate = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2Cz%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2Fz%2Cjob%2Fhr%29+

The combined working rate of all three working together = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2Ct%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2Ft%2Cjob%2Fhr%29+

%28matrix%285%2C1%2C%22A%27s%22%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29%22%22%2B%22%22%28matrix%285%2C1%2C%22B%27s%22%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29 %22%22%2B%22%22 %28matrix%285%2C1%2C%22C%27s%22%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29 %22%22=%22%22 %28matrix%286%2C1%2CTheir%2Ccombined%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29

(4)    1%2Fx%22%22%2B%22%221%2Fy%22%22%2B%22%221%2Fz %22%22=%22%22 1%2Ft

Substituting from (1), (2), and (3) into (4)

      1%2F%28t%2B6%29%22%22%2B%22%221%2F%28t%2B1%29%22%22%2B%22%221%2F%282t%29 %22%22=%22%22 1%2Ft

Multiply through by the LCD, and get t = 2%2F3 hour, after dicarding
the negative value for t.

Substituting in (1), (2), and (3) we get that

A can do 1 job in 20/3 hours.
B can do 1 job in 5/3 hours.
C can do 1 job in 4/3 hours.

But that's not what we are asked to find. What we are asked to find is
given by this sentence:

A and B together can do a job in ____ hours.
A's working rate = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2C20%2F3%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2F%2820%2F3%29%2Cjob%2Fhr%29+ %22%22=%22%22 +matrix%281%2C2%2C3%2F20%2Cjob%2Fhr%29+
 
B's working rate = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2C5%2F3%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2F%285%2F3%29%2Cjob%2Fhr%29+ %22%22=%22%22 +matrix%281%2C2%2C3%2F5%2Cjob%2Fhr%29+ 

Suppose it takes them h hours to complete the job.  Then

The combined working rate of A&B working together = +matrix%281%2C2%2C1%2Cjob%29%2F+matrix%281%2C2%2Ch%2Chr%29+ %22%22=%22%22+matrix%281%2C2%2C1%2Fh%2Cjob%2Fhr%29+


%28matrix%285%2C1%2C%22A%27s%22%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29%22%22%2B%22%22%28matrix%285%2C1%2C%22B%27s%22%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29 %22%22=%22%22 %28matrix%286%2C1%2C%22A%26B%27s%22%2Ccombined%2Cworking%2Crate%2Cin%2Cjob%2Fhr%29%29

3%2F20%22%22%2B%22%223%2F5 %22%22=%22%22 1%2Fh

Multiply through by an LCD, solve and get h = 4/3 hr or 1 hour and 20 minutes.

Edwin