sin[tan-1(3/8)]
This says "Find the sin of the angle whose tangent is 3/8"
So we sketch a right triangle that has an angle whose
tangent is 3/8.
Since the tangent is the opposite over the adjacent, and
3/8 is 3 over 8, we the opposite side as 3, and the adjacent
side as 8.
The angle marked with the red arc is tan-1(3/8),
the angle whose tangent is 3/8.
Now we just need the sine of that angle marked. (Its tangent is 3/8.)
Since the sine is the opposite over the hypotenuse, we will need
to find the hypotenuse:
We use the Pythagorean theorem:
So now we can label the hypotenuse:
Now since the original problem is
sin[tan-1(3/8)]
We find the sine by putting the opposite side 3 over the hypotenuse √73
So the answer is
sin[tan-1(3/8)] = 3/√73
If you like you can rationalize the denominator and get 3√73/73
Edwin