SOLUTION: e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me?

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Question 958894: e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me?
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
e%5E%282x%2B1%29+=+log%2810%2C100%29
e%5E%282x%2B1%29+=+log%2810%2C10%5E2%29
e%5E%282x%2B1%29+=+2log%2810%2C10%29.............log%2810%2C10%29=1
e%5E%282x%2B1%29+=+2........take log of both sides
log%28e%5E%282x%2B1%29+%29=+log%28%282%29%29
%282x%2B1%29+log%28%28e%29%29=+log%28%282%29%29......log%28e%29=1
%282x%2B1%29%2A1=+log%28%282%29%29
2x%2B1=+log%28%282%29%29
2x=+log%28%282%29%29-1
x=+%28log%28%282%29%29-1%29%2F2
x=+%281%2F2%29%28log%28%282%29%29-1%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me?
e%5E%282x+%2B+1%29+=+log+100 ---- Exponential form

e%5E%282x+%2B+1%29+=+2 --------- Converting log 100 to 2

ln 2 = 2x + 1 ------ Logarithmic form

    0.693147 = 2x + 1

0.693147 – 1 = 2x

  - 0.306853 = 2x

x+=+%28-+0.306853%29%2F2, or highlight_green%28x+=+-+0.1534265%29