SOLUTION: Jennifer needs to make a solution that is 10% hydrochloric acid. If she must use all of the 50 mL of 20% hydrochloric acid she started with, then how much water needs to be mixed w

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Jennifer needs to make a solution that is 10% hydrochloric acid. If she must use all of the 50 mL of 20% hydrochloric acid she started with, then how much water needs to be mixed w      Log On

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Question 958833: Jennifer needs to make a solution that is 10% hydrochloric acid. If she must use all of the 50 mL of 20% hydrochloric acid she started with, then how much water needs to be mixed with the original solution?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ml pf water to be added
+.2%2A50+=+10+ ml of HCL in 20% solution
---------------------
+10+%2F+%28+x+%2B+50+%29+=+.1+
+10+=+.1%2A%28+x+%2B+50+%29+
+10+=+.1x+%2B+5+
+.1x+=+5+
+x+=+50+
50 ml of water needs to be added
check:
+10+%2F+%28+x+%2B+50+%29+=+.1+
+10+%2F+%28+50+%2B+50+%29+=+.1+
+10%2F100+=+.1+
+.1+=+.1+
OK