SOLUTION: A motorist was clocked at a certin point traveling at 90 miles per hour. A patrol officer was alerted to chase the motorist. The patrol officer was three miles behind the speedin
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Question 95879: A motorist was clocked at a certin point traveling at 90 miles per hour. A patrol officer was alerted to chase the motorist. The patrol officer was three miles behind the speeding car when he received the message. How fast must the patrol officer have traveled in order to overtake the speeding car in 20 minutes if the car continued to travel 90 miles per hour? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! D=RT
D=90T FOR THE SPEEDER
D=90*1/3
D=30 MILES BEFOR THE COP CATCHES UP.
33 MILES IS THE DISTANCE THE COP MUST TRAVEL IN 1/3 HOUR
33=T/3 CROSS MULTIPLY
T=99 MPH FOR THE COP'S SPEED.
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