SOLUTION: A local hamburger shop sold a combined total of 385 hamburgers and cheeseburgers on Tuesday. There were 65 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold o

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A local hamburger shop sold a combined total of 385 hamburgers and cheeseburgers on Tuesday. There were 65 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold o      Log On


   

Question 958738: A local hamburger shop sold a combined total of 385 hamburgers and cheeseburgers on Tuesday. There were 65 fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Tuesday?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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H=number of hamburgers; C=number of cheeseburgers=H-65
H+C=385 Substitute for C
H+(H-65)=385 Add 65 to each side.
2H=450 Divide each side by 2.
H=225 ANSWER: There were 225 hamburgers sold
CHECK:
C=H-65=225-65=160 There were 160 cheeseburgers sold.
H+C=385
225+160=385
385=385