SOLUTION: In(2x)=5 log base 5(8-3x)= 0.75 log base 4[(3x + 8)(x-6)] =3 log base 2 (x-7) + log base 2 x=3 I have to express all solutions in exact form and show my work on how i g

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: In(2x)=5 log base 5(8-3x)= 0.75 log base 4[(3x + 8)(x-6)] =3 log base 2 (x-7) + log base 2 x=3 I have to express all solutions in exact form and show my work on how i g      Log On


   

Question 958640: In(2x)=5
log base 5(8-3x)= 0.75
log base 4[(3x + 8)(x-6)] =3
log base 2 (x-7) + log base 2 x=3
I have to express all solutions in exact form and show my work on how i got the answer.
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
I'll give you one. They are too much work:
log_5%288-3x%29=+0.75
%28log%288-3x%29%29%2F%28log%285%29%29+=+0.75 I'm going to replace the 0.75 with its fraction equivalent 3/4:
%28log%288-3x%29%29%2F%28log%285%29%29+=+3%2F4
log%288-3x%29+=+%283log%285%29%29%2F4
%283log%285%29%29%2F4++=++log%285%5E%283%2F4%29%29
log%288-3x%29+=+log%285%5E%283%2F4%29%29
8-3x+=+5%5E%283%2F4%29Subtract 8 from both sides:
-3x+=+5%5E%283%2F4%29-8 Lastly, divide both sides by -3:
Your answer is: x+=+8%2F3-5%5E%283%2F4%29%2F3