Question 958631: A bag contains 35 nickels and quarters. The total value of the coins is less than $2.50. What is the max number of quarters that meets these conditions?
Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! N=nickels; Q=quarters
N+Q=35
N=35-Q
$0.05N+$0.25Q=$2.50 Substitute for N
$0.05(35-Q)+$0.25Q=$2.50
$1.75-$0.05Q+$0.25Q=$2.50 Subtract $1.75 from each side.
$0.20Q=$0.75
Q=3.75 To have $2.50, you would have 3.75 quarters, so to have less, the maximum number of (whole) quarters would be 3.
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