SOLUTION: can u help me find the equations in slope intercept form for the line that contains the given point is(a)paralleland(b)perpendicularto the given line.
{{{ (3,-1);2x+2y=5 }}}
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-> SOLUTION: can u help me find the equations in slope intercept form for the line that contains the given point is(a)paralleland(b)perpendicularto the given line.
{{{ (3,-1);2x+2y=5 }}}
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Question 95862: can u help me find the equations in slope intercept form for the line that contains the given point is(a)paralleland(b)perpendicularto the given line. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! can u help me find the equations in slope intercept form for the line that
contains the given point is (a)parallel and (b)perpendicular to the given
line.(3,-1); 2x + 2y = 5
:
Put the equation in the point intercept form (y = mx + b):
2x + 2y = 5
2y = -2x + 5
y = -(2/2)x + 5/2
y = -1x + 2.5
m = -1
:
Parallel lines have the same slope so using m=-1; x1 = 3 and y1 = -1
write the point/slope equation: y - y1 = m(x - x1)
:
y - (-1) = -1(x - 3)
y + 1 = -x + 3
y = -x + 3 - 1
y = -x + 2 is parallel to given line and contains point: 3, -1
:
The relationship between perpendicular lines can be expressed:
m1 * m2 = -1
Substitute -1 for m1 and find m2
-1 * m2 = -1
m2 = +1
:
Use the point/slope equation to find the perpendicular line"
m2 = +1; x1 = 3; y1 =-1
:
y - (-1) = +1(x - 3)
y + 1 = +x - 3
y = x - 3 - 1
y = x - 4 is perpendicular to the given line and contains point: 3, -1
:
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