SOLUTION: I dont think I got this question right but it would help if a tutor would check it and tell me what I did wrong if its wrong. Problem: One of two complementary angles measures 30

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Question 958599: I dont think I got this question right but it would help if a tutor would check it and tell me what I did wrong if its wrong. Problem:
One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle.
x+y= 90
y= 30+3x
3x+30=90
-30 -30
3x=60
3 3
x=20
x= 20
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

two angles (alpha° and beta°) are Complementary Angles if they add up to 90°
so, alpha%2Bbeta=90°
given: one of two complementary angles (let's say alpha) measures 30° +more than three+times the other (let's say beta°)
so, we have that alpha=3beta%2B30° => substitute it in alpha%2Bbeta=90°
3beta%2B30%2Bbeta=90°........solve for beta
4beta=90-30°
4beta=60°
beta=60%2F4°
highlight%28beta=15%29°
now find alpha
alpha=3beta%2B30°
alpha=3%2A15%2B30°
alpha=45%2B30°
highlight%28alpha=75%29°