SOLUTION: Hello, I've been struggling with forming equations from word problems. I love math but word problems are my weakness, I've been stuck here trying to figure out the equations for da

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Question 958413: Hello, I've been struggling with forming equations from word problems. I love math but word problems are my weakness, I've been stuck here trying to figure out the equations for days. My heads already hurting, please help me understand.
The word problem is: the sum of three numbers is 50. The second number is three times the first number, and the third number is twice the second number. What are the numbers?
(I know how to solve equations, i just don't know how to form equations using word problems. )
Found 2 solutions by josmiceli, satyareddy22:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Lt the number be +a+, b+, and c+
(1) +a+%2B+b+%2B+c+=+50+
(2) +b+=+3a+
(3) +c+=+2b+
----------------
(2) +a+=+b%2F3+
Substitute (2) and (3) into (1)
(1) +b%2F3+%2B+b+%2B+2b+=+50+
(1) +b+%2B+3b+%2B+6b+=+150+
(1) +10b+=+150+
(1) +b+=+15+
and
(3) +c+=+2b+
(3) +c+=+30+
and
(2) +a+=+b%2F3+
(2) +a+=+15%2F3+
(2) +a+=+5+
The numbers are 5, 15, and 30
check:
(1) +a+%2B+b+%2B+c+=+50+
(1) +5+%2B+15+%2B+30+=+50+
(1) +50+=+50+
OK

Answer by satyareddy22(84) About Me  (Show Source):
You can put this solution on YOUR website!
Let x,y,z be three numbers.
x+y+z=50------------(1)
y=3x==>x=y/3
z=2y
substituting x=y/3,z=2y in (1)
(y/3)+y+ 2y = 50
=>(y+3y+6y)/3 = 50 =>(y+3y+6y)=150
=>10y=150 =>y=15
x=y/3=15/3=5=>x=5
z=2y=>z=2(15)=30=>z=30
x=5, y=15, z=30