SOLUTION: Write this conic section in standard form. x^2+y^2+6x-2y+9=0

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Question 958077: Write this conic section in standard form. x^2+y^2+6x-2y+9=0
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Write this conic section in standard form. x^2+y^2+6x-2y+9=0
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x^2+6x+9 + y^2-2y+1 = -9+9+1
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(x+3)^2 + (y-1)^2 = 1
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Circle with center at (-3,1); radius = 1
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Cheers,
Stan H.
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Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write this conic section in standard form.
x^2+y^2+6x-2y+9=0
complete the square:
(x^2+6x+9)+(y^2-2y+1)=-9+9+1
(x+3)^2+(y-1)^2=1
This is an equation of a circle with center at (-3,1) and radius=1