SOLUTION: Sally has 100 coins all of which are dimes, nickels, and quarters. She has $13.00 in coins. She has 3 times as many nickels as dimes. How many of each coin does she have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Sally has 100 coins all of which are dimes, nickels, and quarters. She has $13.00 in coins. She has 3 times as many nickels as dimes. How many of each coin does she have?      Log On

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Question 957998: Sally has 100 coins all of which are dimes, nickels, and quarters. She has $13.00 in coins. She has 3 times as many nickels as dimes. How many of each coin does she have?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters

n + d + q = 100
5n + 10d + 25q = 1300
n = 3d

Substitute the third equation into the first two equations.

4d + q = 100
25d + 25q = 1300 ---> d + q = 52

4d + q = 100
-d - q = -52
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3d = 48 --> d = 16

There are 48 nickels, 16 dimes, and 36 quarters.