SOLUTION: Can you help me on a math problem? It reads: The area of a rectangular field is represented by 2x Squared plus 13x plus 21. What are the length and width of the field?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can you help me on a math problem? It reads: The area of a rectangular field is represented by 2x Squared plus 13x plus 21. What are the length and width of the field?      Log On


   

Question 957833: Can you help me on a math problem? It reads: The area of a rectangular field is represented by 2x Squared plus 13x plus 21. What are the length and width of the field?
Found 2 solutions by jsmallt9, stanbon:
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The area of any rectangle is the product of its length and width. Since your rectangle's area is 2x%5E2%2B13x%2B21, this must be the product of its length and width. So all we have to do is to find what factors have a product of 2x%5E2%2B13x%2B21. In other words, we need to factor 2x%5E2%2B13x%2B21:
2x%5E2%2B13x%2B21+=+%28x%2B3%29%282x%2B7%29

So the length and width are (x+3) and (2x+7).

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangular field is represented by 2x Squared plus 13x plus 21. What are the length and width of the field?
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2x^2 + 13x + 21
Factor::
(2x+ 7)(x+3)
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If length = 2x+7, width = x+3
If length = x+3, width = 2x+7
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Cheers,
Stan H.
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