SOLUTION: Note: Remember to show all the steps that you use to solve the problem. You can use the comments field to explain your work. Your teacher will review each step of your response to

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Question 957827: Note: Remember to show all the steps that you use to solve the problem. You can use the comments field to explain your work. Your teacher will review each step of your response to ensure you receive proper credit for your answer.
What is the solution to the proportion?
+3y-8%2F+12+=+y%2F5+
Found 2 solutions by checkley77, Fombitz:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
+3y-8%2F+12+=+y%2F5+
CROSS MULTIPLY
12Y=5(3y-8)
12y=15y-40
12y-15y=-40
-3y=-40
y=-40/-3
y=40/3 ans.
proof:
(3*40/3-8)/12=(40/3)/5
(40-8)/12=40/3*1/5
32/12=40/15
8/3=8/3

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply both sides by 5%2A12=60
60%283y%29-%285%2A12%29%288%2F12%29+=+%285%2A12%29%28y%2F5%29
180y-40=12y
Add -12y to both sides,
180y-12y-40=12y-12y
168y-40=0
Add 40 to both sides,
168y-40%2B40=40
168y%2B0=40
168y=40
Divide both sides by 168
%28168y%29%2F168=40%2F168
%28168%2F168%29y=40%2F168
%281%29y=40%2F168
y=40%2F168
Factor out any common factors in numerator and denominator,
y=%288%2A5%29%2F%288%2A21%29
y=%288%2F8%29%285%2F21%29
y=5%2F21
That's the solution to the problem as written, however it's not a proportion.
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Just in case if the problem was,
%283y-8%29%2F12=y%2F5
Then, multiply both sides by 60.
5%283y-8%29=12y
Distribute the 5} on the left hand side.
15y-40=12y
Subtract 12y from both sides,
15y-12y-40=12y-12y
3y-40=0
Add 40 to both sides,
3y-40%2B40=40
3y%2B0=40
3y=40
Divide both sides by 3.
%283y%29%2F3=40%2F3
%283%2F3%29y=40%2F3
%281%29y=40%2F3
y=40%2F3