SOLUTION: fine three consecutive odd integers such that the sum of the last two is 15 less than five times the first

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Question 957785: fine three consecutive odd integers such that the sum of the last two is 15 less than five times the first

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE FIRST ODD INTEGER.
LET X+2 BE THE NEXT ODD INTEGER.
LET X+4 BE THE NEXT ODD INTEGER.
(X+2)+(X+4)=5X-15
2X+6=5X-15
2X-5X=-15-6
-3X=-21
X=-21/-3
X=7 ANS.
7+2=9 ANS.
7+4=11 ANS.
PROOF:
9+11=5*7-15
20=35-15
20=20