SOLUTION: Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits

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Question 957726: Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number.
The difference of the original two-digit number and the number with reversed digits is
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number.
The difference of the original two-digit number and the number with reversed digits is
***
let u=units digit
let t=tens digit
..
5(u+t)=10t+u-13
4(u+t)=10u+t-21
..
5u+5t=10t+u-13
4u+4t=10u+t-21
..
4u-5t=-13
-6u+3t=-21
..
24u-30t=-78
-24u+12t=-84
add
-18t=-162
t=9
4u-5t=-13
4u=-13+5t=-13+45=32
u=8
original number=98
reversed number=10u+t=89
difference of the original two-digit number and the number with reversed digits is 9