SOLUTION: Find two consecutive integers such that the square of the smaller plus twice the larger is 50.

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Question 957562: Find two consecutive integers such that the square of the smaller plus twice the larger is 50.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE SMALLER INTEGER.
LET X+1 BE THE SECOND INTEGER.
X^2+2(X+1)=50
X^2+2X+2-50=0
X^2+2X-48=0
(X+8)(X-6)=0
X-6=0
X=6 ANS.
PROOF:
6^2+2(6+1)=50
36+2*7=50
36+14=50
50=50