SOLUTION: The half-life of an isotope is the time for its mass to decay by ½. For example, polonium-210 has a half-life of 40. So, a sample of 100 g would decay to 50 g in 40 weeks. The pe

Algebra ->  Finance -> SOLUTION: The half-life of an isotope is the time for its mass to decay by ½. For example, polonium-210 has a half-life of 40. So, a sample of 100 g would decay to 50 g in 40 weeks. The pe      Log On


   



Question 957506: The half-life of an isotope is the time for its mass to decay by ½. For example, polonium-210 has a half-life of 40. So, a sample of 100 g would decay to 50 g in 40 weeks. The percent, P, of polonium remaining after t weeks is given by the formula . What percent of polonium remains after 30 weeks?Show your work for full marks. (2 mark)

Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
"The formula" might be P=Ie^(-kt) where I is the initial percent of polonium. What is not clear is your description for half-life. 40 WHAT?

Half-life of polonium 210 is 138.4 days. What is the unit of "40"? This is unclear.

Ordinarily, advice would be use half-life information to find the k value, and then solve the question part of the problem using this k value.

highlight%28P=Ie%5E%28-kt%29%29
ln%28P%29=ln%28I%29-kt
ln%28P%2FI%29=-kt
highlight_green%28k=ln%28I%2FP%29%2Ft%29