SOLUTION: If cosA = -6/7, in quadrant 2, determine the exact value of tan2A.
I found the opposite of angle A to be {{{ sqrt(85) }}} by making a right-angled triangle.
After using doubl
Algebra ->
Trigonometry-basics
-> SOLUTION: If cosA = -6/7, in quadrant 2, determine the exact value of tan2A.
I found the opposite of angle A to be {{{ sqrt(85) }}} by making a right-angled triangle.
After using doubl
Log On
Question 957480: If cosA = -6/7, in quadrant 2, determine the exact value of tan2A.
I found the opposite of angle A to be by making a right-angled triangle.
After using double angle formula for tangent, I get an exact answer of but I'm not sure if it's correct. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! If cosA = -6/7, in quadrant 2, determine the exact value of tan2A.
I found the opposite of angle A to be by making a right-angled triangle.
After using double angle formula for tangent, I get an exact answer of but I'm not sure if it's correct.
--------------------
You can use a calculator to check.
It's not correct.
