SOLUTION: sin2x+cosx=0
I thought that because there was sin2x; this meant I had to use sin x(2cosx-1)=0
sinx =0, 180;
2cosx-1=0
cosx =1/2= 60, 300
However; the answer is speci
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-> SOLUTION: sin2x+cosx=0
I thought that because there was sin2x; this meant I had to use sin x(2cosx-1)=0
sinx =0, 180;
2cosx-1=0
cosx =1/2= 60, 300
However; the answer is speci
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Question 957001: sin2x+cosx=0
I thought that because there was sin2x; this meant I had to use sin x(2cosx-1)=0
sinx =0, 180;
2cosx-1=0
cosx =1/2= 60, 300
However; the answer is specified as being 90,210, 270, 330
Where I have gone wrong Answer by macston(5194) (Show Source):
