SOLUTION: 6. Factor completely: x^2-3x-28 (x-7)(x+4) (x-7)(x-4) (x+7)(x-4 (x+7)(x+4)

Algebra ->  Finance -> SOLUTION: 6. Factor completely: x^2-3x-28 (x-7)(x+4) (x-7)(x-4) (x+7)(x-4 (x+7)(x+4)       Log On


   

Question 956977: 6. Factor completely: x^2-3x-28
(x-7)(x+4)
(x-7)(x-4)
(x+7)(x-4
(x+7)(x+4)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Factor completely: x^2-3x-28
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Find a pair of factors of 28 that differ by 3.