SOLUTION: Find 4 consecutive odd integers whose sum of the lowest number and 5 more than 3 times the highest number is 89

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Question 956892: Find 4 consecutive odd integers whose sum of the lowest number and 5 more than 3 times the highest number is 89
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let the four odd integers be,
N-2,N, N%2B2, and N%2B4
So then,
%28N-2%29%2B3%28N%2B4%29%2B5=89
N-2%2B3N%2B12%2B5=89
4N%2B15=89
4N=74
N=37%2F2
The solution should be an integer.
Please check your problem set up and repost a corrected problem.