SOLUTION: With all steps showing how the domain is reached in set form n^2+13n+40 numerator 8n denominator This is in fraction form with 8n being the denominator

Algebra ->  Functions -> SOLUTION: With all steps showing how the domain is reached in set form n^2+13n+40 numerator 8n denominator This is in fraction form with 8n being the denominator       Log On


   

Question 956844: With all steps showing how the domain is reached in set form
n^2+13n+40 numerator
8n denominator
This is in fraction form with 8n being the denominator
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%28n%5E2%2B13n%2B40%29%2F%288n%29=%28%28n%2B5%29%28n%2B8%29%29%2F%288n%29
The only problem encountered in the domain occurs when the denominator goes to zero since division by zero is undefined.
So the only value for n that is not allowed is n=0.
So the domain is (-infinity,0)U(0,infinity).