SOLUTION: Find three consecutive odd integers such that twice the first less the third is 7.

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Question 956817: Find three consecutive odd integers such that twice the first less the third is 7.
Answer by macston(5194) About Me  (Show Source):
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three consecutive odd integers:n,n+2,n+4
2n-(n+4)=7
n-4=7
n=11 ANSWER 1: The first integer is 11.
n+2=13 ANSWER 2: The second integer is 13.
n+4=15 ANSWER 3: The third number is 15.