SOLUTION: We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?

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Question 956645: We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
We have 10 guest house and 7 guest.What is the number of permutations that we can arrange them ?
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Ans: 10P7 = 10!/3! = 604800 ways
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Cheers,
Stan H.