SOLUTION: Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
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Question 956600: Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
You can put this solution on YOUR website! Eight times the sum of the digits of a certain two-digit number exceeds the number by 19. The tens digit is two less than the units digit. Find the number.
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let u=units digit
let t=tens digit
t=u-2
..
8(t+u)=10t+u+19
8t+8u=10(u-2)+u+19
8(u-2)+8u=10u-20+u+19
8u-16+8u=10u-20+u+19
5u=15
u=3
t=u-2=1
number=10t+u=10+3=13