SOLUTION: the perimeter of a rectangle is 56 inches. the width of the rectangle is 14 inches less than the length of the rectangle. find the dimensions of the rectangle. How do i solve this
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Question 956391: the perimeter of a rectangle is 56 inches. the width of the rectangle is 14 inches less than the length of the rectangle. find the dimensions of the rectangle. How do i solve this by steps? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! L=length; W=width=L-14in; P=perimeter=56 inches
P=2(L+W) Substitute for W
56 inches=2(L+L-14in) Divide each side by 2.
28 inches=2L-14 inches Add 14 inches to each side.
42 inches=2L Divide each side by 2.
21 inches=L ANSWER 1: The length is 21 inches.
W=L-14 inches=21 inches-14 inches=7 inches ANSWER 2: The width is 7 inches.
CHECK:
P=2(L+W)
56 inches=2(21 inches+7inches)
56 inches=2(28 inches)
56 inches=56 inches
