Question 956245: A box contains 80 coins only dimes and nickles the box has $6.10 how many dimes and nickles are in the box? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A box contains 80 coins only dimes and nickles the box has $6.10 how many dimes and nickles are in the box?
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Equations:
n + d = 80 coins
5n+10d = 610 cents
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Modify for elimination::
5n + 5d = 5*80
5n + 10d = 610
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Subtract and solve for "d"::
5d = 210
d = 42 (# of dimes)
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Solve for "n":
n + d = 80
n + 42 = 80
n = 38 (# of nickels)
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cheers,
Stan H.
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