SOLUTION: 3 married couples have bought 6 seats in the same row for a rock concert. In how many different ways can they be seated; a) with no res

Algebra ->  Probability-and-statistics -> SOLUTION: 3 married couples have bought 6 seats in the same row for a rock concert. In how many different ways can they be seated; a) with no res      Log On


   

Question 956173: 3 married couples have bought 6 seats in the same row for a rock concert.
In how many different ways can they be seated;
a) with no restrictions.
b) if each couple is to sit together.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3 married couples have bought 6 seats in the same row for a rock concert.
In how many different ways can they be seated;
a) with no restrictions.
Ans: 6P6 = 6! = 720
-------------------------
b) if each couple is to sit together.
Arrange the 3 pairs:: 3! = 6 ways
Arrange each of the couples = 2^3 = 8
-----------
Ans: 3!*2^3 = 6*8 = 48
--------------------
Cheers,
Stan H.
-------------