SOLUTION: Two planes just took off from Salt Lake City, UT. The first plane is traveling 4 times as fast as the second plane. After traveling in the same direction for 5 hours, they are 1590

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Question 956108: Two planes just took off from Salt Lake City, UT. The first plane is traveling 4 times as fast as the second plane. After traveling in the same direction for 5 hours, they are 1590 miles apart. What is the average speed of each plane?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = distance in miles the slower plane flies in 5 hrs
Let +d+%2B+1590+ = distance in miles the faster plane flies in 5 hrs
Let +s+ = the speed in mi/hr of the slower plane
+4s+ = the speed in mi/hr of the faster plane
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Equation for slower plane:
(1) +d+=+s%2A5+
Equation for faster plane:
(2) +d+%2B+1590+=+4s%2A5+
------------------------
Substitute (1) into (2)
(2) +5s+%2B+1590+=+20s+
(2) +15s+=+1590+
(2) +s+=+106+
and
+4s+=+424+
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The average speed of the slower plane is 106 mi/hr
The average speed of the faster plane is 424 mi/hr
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check:
(1) +d+=+106%2A5+
(1) +d+=+530+
and
(2) +d+%2B+1590+=+20%2A106+
(2) +d+=+2120+-+1590+
(2) +d+=+530+
OK