SOLUTION: find 3 consecutive even integers such that 4 times the sum of the first and second minus 7 is 6 times the third increased by 9

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Question 956041: find 3 consecutive even integers such that 4 times the sum of the first and second minus 7 is 6 times the third increased by 9
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

4((x-2) + x) - 7 = 6(x+2) + 9
4(2x - 2) - 7 = 6(x + 2) + 9
8x - 8 - 7 = 6x + 12 + 9
8x - 15 = 6x + 21
2x = 36
x = 18

The integers are 16, 18, and 20.