SOLUTION: Please help!!! Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arri

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Question 955983: Please help!!!
Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute late. How far does Michael live from work? What speed does he need to drive to arrive 5 minutes early?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the speed in mi/hr that he
has to drive to arrive on time at work
Let +t+ = time to get to work when
he arrives on time
Let +d+ = distance in miles to work
-----------------------------------
Arriving 1 min early:
(1) +d+=+45%2A%28+t+-+1%2F60+%29+
Arriving 1 min late:
(2) +d+=+40%2A%28+t+%2B+1%2F60+%29+
-----------------------
+45%2A%28+t-1%2F60+%29+=+40%2A%28+t%2B1%2F60+%29+
+45t+-+45%2F60+=+40t+%2B+40%2F60+
+5t+=+85%2F60+
+t+=+17%2F60+ hrs
------------
(2) +d+=+40%2A%28+t+%2B+1+%29+
(2) +d+=+40%2A%28+17%2F60+%2B+1+%29+
(2) +d+=+3080%2F60+
(2) +d+=+154%2F3+
(2) +d+=+51.333+
He lives 51.333 mi from work
-------------------
arriving 5 min early:
(1) +d++=+s%2A%28+1+-+5%2F60+%29+
(1) +154%2F3+=+s%2A%28+55%2F60+%29+
(1) +154%2F3+=+s%2A%28+11%2F12+%29+
(1) +616%2F12+=+s%2A%28+11%2F12+%29+
(1) +11s+=+616+
(1) +s+=+56+
---------------
He has to drive 56 mi/hr to arrive 5 min early