SOLUTION: Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute
Log On
Question 955979: Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute late. How far does Michael live from work? What speed does he need to drive to arrive 5 minutes early? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Michael drove to work on Monday at 45 mph and arrived one minute early. The employee drove to work on Tuesday, leaving home at the same time driving 40 mph and arriving one minute late. How far does Michael live from work? What speed does he need to drive to arrive 5 minutes early?
***
min=1/60 hr
d=distance
s=speed
let x=0n-time travel time
distance/speed=travel time
d/45=x-(1/60)
d/40=x+(1/60)
45(x-(1/60)=40(x+(1/60)
45x-45/60=40x+40/60
5x=95/60
x=95/300 hr or 19 min (on-time travel time)
d=45(x-(1/60)=45(95/300-5/300)=45(90/300)=13.5 mi
d/s=95/300-5/60
13.5/s=95/300-25/300=70/300
s=13.5/(70/300)≈57.86 mph
How far does Michael live from work? 13.5 mi
What speed does he need to drive to arrive 5 minutes early? 57.86 mph
(