SOLUTION: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?      Log On


   

Question 955974: Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Person A can paint the neighbor's house 5 times as fast as Person B. The year A and B worked together, it took them 7 days. How long would it take each to paint the house?
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let x=number of days A can finish painting the house by himself
his work rate=1/x
5x=number of days B can finish painting the house by himself
his work rate=1/5x
7=number of days both A and B working together can finish painting
Their work rate=1/7
..
sum of indv. work rates=work rate working together
1%2Fx%2B1%2F5x=1%2F7
lcd:5x
5+1=5x/7
5x=42
x=42/5=8.4
5x=42
number of days A can finish painting the house by himself=8.4
number of days B can finish painting the house by himself=42