SOLUTION: Tutor, Good evening I am have difficulties with this problem could you help me? Solve each of the following quadratic equations. 4x^2 = 13x + 12 I am so confused on

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Tutor, Good evening I am have difficulties with this problem could you help me? Solve each of the following quadratic equations. 4x^2 = 13x + 12 I am so confused on      Log On


   

Question 95597This question is from textbook Beginning Algebra
: Tutor,
Good evening I am have difficulties with this problem could you help me?
Solve each of the following quadratic equations.
4x^2 = 13x + 12
I am so confused on how to solve this problem. Thanks in advance for your help. This question is from textbook Beginning Algebra

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve each of the following quadratic equations.
4x^2 = 13x + 12
4x^2-13x-12 = 0
Use the quadratic formula to get:
x = [13 +- sqrt(13^2-4*4*-12)]/8
x = [13 +- sqrt(361)]/8
x = [13 +- 19]/8
x = 4 or x = -3/4
=================

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-13x-12=0
Quadratic formula:x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
%2813%2B-sqrt%28169-%284%2A4%2A-12%29%29%29%2F8
%2813%2B-sqrt%28169-%28-192%29%29%29%2F8
%2813%2B-sqrt%28169%2B192%29%29%2F8
(13+-(19))/8
x=32/8 and x=-6/8
x=4 and x=-3/4
EdJones