SOLUTION: If the product of 2 positive numbers is 27, and one number is 6 greater than the other, what are the two numbers?

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Question 955877: If the product of 2 positive numbers is 27, and one number is 6 greater than the other, what are the two numbers?
Found 3 solutions by Alan3354, macston, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
L=larger number; S=smaller number
L-S=6
L=S+6
L*S=27 Substitute for L.
(S+6)(S)=27
S^2+6S=27 Subtract 27 from each side.
S^2+6S-27=0
(S+9)(S-3)
S=-9 or S=3 ANSWER: The smaller number is 3.
L=S+6=3+6=9 ANSWER 2: The larger number is 9

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = the smaller number
+n+%2B+6+ = the larger number
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given:
+n%2A%28+n+%2B+6+%29+=+27+
+n%5E2+%2B+6n+-+27+=+0+
+%28+n+%2B+9+%29%2A%28+n+-+3+%29+=+0+
+n+=+3+
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+n%2B6+=+9+
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The numbers are 3 and 9
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also, the other solution is:
+n+=+-9+
+n+%2B+6+=+-3+
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The numbers are -3 and -9
also