SOLUTION: Hypothesis Testing.
Ho: population mean μo = 200
Ha: population mean μo < 200
This will be Left-Tailed test.
Population Standard Deviation σ = 50
Significa
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-> SOLUTION: Hypothesis Testing.
Ho: population mean μo = 200
Ha: population mean μo < 200
This will be Left-Tailed test.
Population Standard Deviation σ = 50
Significa
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Question 955797: Hypothesis Testing.
Ho: population mean μo = 200
Ha: population mean μo < 200
This will be Left-Tailed test.
Population Standard Deviation σ = 50
Significance level is 0.10 (10%).
Critical z-value for 10% significance level and Left-Tailed test is (-1.28).
For sample mean 194 and sample size 36 use numbers assigned for in the table below.
1. Calculate your test statistics z-value: z = (194 - 200)/(50/√36)
2. Does your sample statistics z value falls in rejection region to the left of -1.28? 3. Will you reject or do not reject Ho?
You can put this solution on YOUR website! Hypothesis Testing.
Ho: population mean μo = 200
Ha: population mean μo < 200
This will be Left-Tailed test.
-----------------------------
Population Standard Deviation σ = 50
Significance level is 0.10 (10%).
Critical z-value for 10% significance level and Left-Tailed test is (-1.28).
---------------------------
For sample mean 194 and sample size 36 use numbers assigned for in the table below.
1. Calculate your test statistics z-value: z = (194 - 200)/(50/√36)
z(194) = (194-200)/[50/sqrt(36)] = = -0.02
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2. Does your sample statistics z value fall in rejection region to the left of
-1.28?
Ans: No, it is not that far below the mean.
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3. Will you reject or do not reject Ho?
Ans: Since the test stat is not in the reject interval
you should fail to reject Ho.
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Cheers,
Stan H.
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