SOLUTION: Find the shortest distance from the circle x^2+y^2+8x-6y=0 to the circle x^2+y^2-12x-4y+24=0. Draw the figure.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the shortest distance from the circle x^2+y^2+8x-6y=0 to the circle x^2+y^2-12x-4y+24=0. Draw the figure.      Log On


   

Question 955761: Find the shortest distance from the circle x^2+y^2+8x-6y=0 to the circle x^2+y^2-12x-4y+24=0. Draw the figure.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y^2+8x-6y=0 to the circle x^2+y^2-12x-4y+24=0
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For each circle, find the center and the radius.
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The distance between the centers minus the sum of the radii = shortest distance.
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